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- Dictionarydistinct/dɪˈstɪŋ(k)t/
adjective
- 1. recognizably different in nature from something else of a similar type: "the patterns of spoken language are distinct from those of writing" Similar Opposite
- 2. readily distinguishable by the senses: "a distinct smell of nicotine"
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To do this, you need to use an aggregate function to sort on, and use a GROUP BY to make the DISTINCT work. Try something like this: SELECT DISTINCT Category, MAX(CreationDate) FROM MonitoringJob. GROUP BY Category. ORDER BY MAX(CreationDate) DESC, Category. edited Dec 28, 2017 at 15:48.
Mar 31, 2010 · Interesting scenario. As you found, SELECT DISTINCT(a), b, c. is equivalent to: SELECT DISTINCT (a), b, c. is equivalent to: SELECT DISTINCT a, b, c. i.e. the parentheses are treated as expression grouping parentheses. Interestingly, a very similar issue occurs in VB6/VBScript where (for Function (byref x)) Function (x), Function x and Call ...
Jun 19, 2016 · 11. DISTINCT (or DISTINCTROW) is not a function; it is an option of the SELECT statement that tells MySQL to strip duplicate rows from the resultset generated by the query. By default it returns all the generated rows, including the duplicates. It can also be used together with COUNT() aggregate function (as COUNT(DISTINCT expr)) and it has the ...
4. Entity-Framework Select Distinct Name: Suppose if you are using Views in which you are using multiple tables and you want to apply distinct in that case first you have to store value in variable & then you can apply Distinct on that variable like this one.... public List<Item_Img_Sal_VIEW> GetItemDescription(int ItemNo)
Jan 29, 2009 · 98. Starting with .NET 6, there is new solution using the new DistinctBy() extension in Linq, so we can do: var distinctPersonsById = personList.DistinctBy(x => x.Id); The signature of the DistinctBy method: // Returns distinct elements from a sequence according to a specified. // key selector function.
While query select distinct count(a) will give you list of unique counts of values in a. Without grouping it will be just one line with total count. See following example. create table t(a int) insert into t values (1),(2),(3),(3) select count (distinct a) from t select distinct count (a) from t group by a
Considering the same table this could give the result. SELECT EmailAddress, CustomerName FROM Customers as a. Inner Join Customers as b on a.CustomerName <> b.CustomerName and a.EmailAddress = b.EmailAddress. For still better results I would suggest you to use CustomerID or any unique field of your table.
Nov 29, 2017 · so that 3 classes Apple, Orange and Banana are distinct types, and 3 classes DriedApple, DriedOrange, DriedBanana are distinct types. My question is somewhat similar to How to define different types for the same class in C++ , except that I want to explicitly store information about class type as enum member variable in the class, and to have a common base class for all distinct types.
Having done so, you can also write your own extension method that takes a delegate. Cool! If someone missed it you can do: source.DistinctBy (x => new { x.A, x.B }); TIdentity should have a IEquatable<TIdentity> constraint, and therefore, use the identitySelector(x).Equals(identitySelector(y)) instead.
Feb 28, 2013 · This will be O(n) where n is the number of objects in array and m is the number of unique values. There is no faster way than O(n) because you must inspect each value at least once.
