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  1. Apr 22, 2015 · You don't need to escape forward slash. This works for me: #include <stdio.h> int main() { printf("| /\\ /\\ |"); printf("| \\/ \\/ |"); return 0; }

  2. Jan 16, 2019 · Assuming this question is about outputting some supplied data: No character has to be escaped in a special way (apart from from the shell) if printf is used properly. For example: printf '%s\n' '\' , or printf '%s\n' '%' .

  3. The most common is GNU getopt style, with one dash for short options and two dashes for long options. Initially, Unix programs took single-letter options preceded by a single dash and optionally bundled: ls -laF. ls -l -a -F. The two commands above are equal.

  4. Jul 1, 2007 · The combination of a dot followed directly by a forward slash (./) is often used to precede commands in Linux and other Unix-like operating systems. Although this requirement can seem confusing and even tedious to new users, it exists for good reason and can be useful to understand.

  5. justforjava.com › escape-sequencesjust for java

    hope you know the difference between forward slashes and backslashes by now! your goal is to use escape sequences to print out 6 forward slashes and 6 backslashes. this will require two steps: use next-line printing to print out 6 forward slashes. in case you forgot, a forward slash is /.

  6. Short options (e.g. cut -d ' ') can have arguments , while long options (e.g. ls --all) don't necessarily have them. To set a particular behavior of a program, you sometimes need to use a short option, for others you need to use a long option, and for some you have a choice.

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  8. Mar 10, 2022 · The Bash printf command lets you write to a Linux terminal window with finer control and more formatting options than the echo command provides. Even printf 's odd quirks can be useful. Writing to a Terminal

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