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   Can an unsigned integer overflow?

   • A computation involving unsigned operands can never overflow, because a result that cannot be represented by the resulting unsigned integer type is reduced modulo the number that is one greater than the largest value that can be represented by the resulting type. However, both standards state that signed integer overflow is undefined behavior.

   c++ - Why is unsigned integer overflow defined behavior but signed integer overflow isn't? - Stack Overflow

   stackoverflow.com/questions/18195715/why-is-unsigned-integer-overflow-defined-behavior-but-signed-integer-overflow-is

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   Does unsigned arithmetic ignore overflow?

   • Unsigned arithmetic in C ignores overflow; it produces the true result modulo the n th power of 2, where n is the number of bits in the data type. We say it “truncates” the true result to the lowest n bits. A true result that is negative, when taken modulo the n th power of 2, yields a positive number. For instance,

   Unsigned Overflow (GNU C Language Manual)

   www.gnu.org/software/c-intro-and-ref/manual/html_node/Unsigned-Overflow.html

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   Can a computation involving unsigned operands overflow?

   • A computation involving unsigned operands can never overflow, because a result that cannot be represented by the resulting unsigned integer type is reduced modulo the number that is one greater than the largest value that can be represented by the resulting type. This makes unsigned integer types a special case.

   c++ - Why is unsigned integer overflow defined behavior but signed integer overflow isn't? - Stack Overflow

   stackoverflow.com/questions/18195715/why-is-unsigned-integer-overflow-defined-behavior-but-signed-integer-overflow-is

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   Why does a negative number -1 cause overflow?

   • For instance, causes overflow because the negative number -1 can’t be stored in an unsigned type. The actual result, which is -1 modulo the n th power of 2, is one less than the n th power of 2. That is the largest value that the unsigned data type can store. For a 32-bit unsigned int, the value is 4,294,967,295. See Maximum and Minimum Values.

   Unsigned Overflow (GNU C Language Manual)

   www.gnu.org/software/c-intro-and-ref/manual/html_node/Unsigned-Overflow.html

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   What is an example of an unsigned overflow?

   • This is an example of an unsigned overflow, where the value couldn't be stored in the available no. of bytes. In such overflows, the result is moduloed by range (here, 256). If a is 100 (01100100) and b is 50 (00110010), a+b is 150 (10010110), which is more than the max value 127. Instead, a+b will be read as -106 (note that -106=150-256).

   Integer overflow - C++ Articles - C++ Users

   cplusplus.com/articles/DE18T05o/

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   How to analyze overflow in unsigned integer addition?

   • Let us analyze overflow in unsigned integer addition. Consider 2 variables a and b of a data type with size n and range R. Let + be actual mathematical addition and a$b be the addition that the computer does. If a+b<=R-1, a$b=a+b As a and b are unsigned, a$b is more or equal to than both a and b.

   Integer overflow - C++ Articles - C++ Users

   cplusplus.com/articles/DE18T05o/

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2. stackoverflow.com › questions › 16056758C/C++ unsigned integer overflow - Stack Overflow

   stackoverflow.com › questions › 16056758

   Apr 17, 2013 · A computation involving unsigned operands can never overflow, because a result that cannot be represented by the resulting unsigned integer type is reduced modulo to the number that is one greater than the largest value that can be represented by the resulting type.

3. en.wikipedia.org › wiki › Integer_overflowInteger overflow - Wikipedia

   en.wikipedia.org › wiki › Integer_overflow

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   When an unsigned arithmetic operation produces a result larger than the maximum above for an N-bit integer, an overflow reduces the result to modulo N-th power of 2, retaining only the least significant bits of the result and effectively causing a wrap around.

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5. www.geeksforgeeks.org › how-do-i-detect-unsignedHow Do I Detect Unsigned Integer Overflow in C++?

   www.geeksforgeeks.org › how-do-i-detect-unsigned

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   Apr 16, 2024 · The most simple and efficient method to detect the unsigned integer overflow is to check for overflow before performing an arithmetic operation. This involves comparing the operands against the maximum value that the type can hold before performing the operation. Approach.

6. www.gnu.org › html_node › Unsigned-OverflowUnsigned Overflow (GNU C Language Manual)

   www.gnu.org › html_node › Unsigned-Overflow

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   6.3.1 Overflow with Unsigned Integers. Unsigned arithmetic in C ignores overflow; it produces the true result modulo the n th power of 2, where n is the number of bits in the data type. We say it “truncates” the true result to the lowest n bits.

7. cplusplus.com › articles › DE18T05oInteger overflow - C++ Articles - C++ Users

   cplusplus.com › articles › DE18T05o

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   Jun 9, 2012 · This is an example of an unsigned overflow, where the value couldn't be stored in the available no. of bytes. In such overflows, the result is moduloed by range (here, 256). If a is 100 (01100100) and b is 50 (00110010), a+b is 150 (10010110), which is more than the max value 127.

8. www.learncpp.com › cpp-tutorial › unsigned-integers4.5 — Unsigned integers, and why to avoid them – Learn C++

   www.learncpp.com › cpp-tutorial › unsigned-integers

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   Aug 29, 2024 · The answer is overflow. Oddly, the C++ standard explicitly says “a computation involving unsigned operands can never overflow”. This is contrary to general programming consensus that integer overflow encompasses both signed and unsigned use cases (cite).

9. www.geeksforgeeks.org › how-to-avoid-integerHow to Avoid Integer Overflows and Underflows in C++?

   www.geeksforgeeks.org › how-to-avoid-integer

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   Apr 6, 2023 · In C++, unsigned integer is a datatype that can store only zero and non-negative integer values. According to C++ standard, unsigned integer overflow is defined behavior (as it wraps around using modulo arithmetic and starts again from 0).