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The pressure gauge on her air tank reads \(6.9 \times 10^6 \, Pa\). What force does the air inside the tank exert on the flat end of the cylindrical tank, a disk 0.150 m in diameter? Strategy. We can find the force exerted from the definition of pressure (Equation \red{pressure}) provided we can find the area \(A\) acted upon. Solution
- Density
Define density. Calculate the mass of a reservoir from its...
- 10.2: Pressure
We know from Equation \(\ref{10.2.1}\) that applying the...
- Density
Dec 28, 2020 · Pressure is a key concept in physics, whether you're interested in how meteorologists predict the weather, or you want to describe the Carnot cycle in thermodynamics. Pressure is the force on a surface per unit area, and it has a close link to the temperature of the liquid or gas creating it.
When a force of ‘F’ Newton is applied perpendicularly to a surface area ‘A’, then the pressure exerted on the surface by the force is equal to the ratio of F to A. The formula for pressure (P) is: P = F / A . Units of Pressure. There are various units to describe Pressure some of which we will discuss further in this article.
- 5 min
We know from Equation \(\ref{10.2.1}\) that applying the same force to a smaller area produces a higher pressure. When we use a hose to wash a car, for example, we can increase the pressure of the water by reducing the size of the opening of the hose with a thumb. The units of pressure are derived from the units used to measure force and area.
The pressure exerted by a column of liquid of height h and density ρ is given by the hydrostatic pressure equation p = ρgh, where g is the gravitational acceleration. Fluid density and local gravity can vary from one reading to another depending on local factors, so the height of a fluid column does not define pressure precisely.
Pressure. Pressure (p) is defined as the normal force F per unit area A over which the force is applied, or \[p = \frac{F}{A} \ldotp \label{14.3}\] To define the pressure at a specific point, the pressure is defined as the force dF exerted by a fluid over an infinitesimal element of area dA containing the point, resulting in p = \(\frac{dF}{dA}\).
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The pressure exerted by a static liquid depends only on the depth, density of the liquid, and the acceleration due to gravity. gives the expression for pressure as a function of depth within an incompressible, static liquid as well as the derivation of this equation from the definition of pressure as a measure of energy per unit volume (ρ is the density of the gas, g is the acceleration due ...