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5. Re-arranging Equations. 5. Re-arranging Equations Step Up to GCSE Physics. Many equations in Physics involve three quantities. On these pages, we practise re-arranging equations so that we can calculate what we need. Let’s use the equation A= b×c, usually written A = bc. If b = 2 and c =5, then A = b×c = 2×5= 10. We can get c = 5 from 5 ...
Let’s summarise now what we’ve learned about rearranging formulas for physical quantities. Starting off, we saw that, in a formula, for example, an imaginary formula 𝐴 is equal to 𝐵 times 𝐶, the quantity that’s isolated on one side of that formula is called the subject. In the case of this equation, 𝐴 equals 𝐵 times 𝐶 ...
By rearranging the equation for impulse to solve for force F net = Δ p Δ t, F net = Δ p Δ t, you can see how increasing Δ t Δ t while Δ p Δ p stays the same will decrease F net. This is another example of an inverse relationship. Similarly, a padded dashboard increases the time over which the force of impact acts, thereby reducing the ...
The above formula must be rearranged to make V the subject:-. Step 1 : Move the "divide by t " across the equals sign and change to "multiply by t":-. Step 2: Move the "subtract by u" across the equals sign and change to "add by u":-. Step 3 : Rewrite with the subject on the left:-.
- Simplifying A Difficult Problem
- Your Turn to Practice
- What's Up with The Normal Force?
Consider the situation below in which a force is directed at an angle to the horizontal. In such a situation, the applied force could be resolved into two components. These two components can be considered to replace the applied force at an angle. By doing so, the situation simplifies into a familiar situation in which all the forces are directed h...
To test your understanding, analyze the two situations below to determine the net force and the acceleration. When finished, click the button to view the answers.
There is one peculiarity about these types of problems that you need to be aware of. The normal force (Fnorm) is not necessarily equal to the gravitational force (Fgrav) as it has been in problems that we have previously seen. The principle is that the vertical forces must balance if there is no vertical acceleration. If an object is being dragged ...
To calculate how far it would land from its initial position we can use the expression for position in Equation 8.2.16 in the x-direction and the time obtained in Equation 8.2.20: xf = xo + vo, xt = (vocosθ)(2vosinθ g) = 2v2 ocosθsinθ g = v2 osin(2θ) g. where in the last step we used a trigonometric identity.
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Solution The component equations follow from the vector equations above. We see that block 1 has the vertical forces balanced, so we ignore them and write an equation relating the x-components. There are no horizontal forces on block 2, so only the y-equation is written. We obtain these results:
