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      • To find the tangent line, you take the derivative of the curve at the point in question. The derivative tells you the slope of the curve at that point, so a line with that slope can be drawn through the point. This line is the tangent line. You can then use the tangent line to approximate the behavior of the curve near that point.
  1. Sep 3, 2018 · Find the equation of the tangent line of $e^{x-y}(2x^2+y^2)$ at the point $(1,0)$ at the level curve. So I start finding the gradient of the function $gradf={e^{x-y}(2x^2+y^2)+4xe^{x-y} \choose -e^{x-y}(2x^2+y^2)+2ye^{x-y}}$

    • vector analysis

      The text book question is $f(x,y)=xy$, find the gradient...

  2. Finding the equation of a tangent line to a level curve at a given point. ...more.

    • 7 min
    • 1472
    • Bob Davis
  3. . THEOREM 15.12. The Gradient and Level Curves. Given a function. f. differentiable at. (a,b) , the line tangent to the level curve of. f. at. (a,b) is orthogonal to the gradient. ∇f(a,b) , provided. ∇f(a,b)≠0. . Proof: Consider the function. z=f(x,y)

  4. Nov 4, 2015 · Tangent Line to a given level curve Folders: https://drive.google.com/open?id=0Bzl...

    • 37 min
    • 10.4K
    • Calc STCC Math Department Professor R.Burns
  5. find the points (a, b) (a, b) of the plane that satisfy the tangent of the level curve M = f(a, b) M = f (a, b) in the point (a, b) (a, b) passes through (0, 1) (0, 1). I tried solving this simply by using the equation of the tangent to a level curve: fx(a, b)(x − a) +fy(a, b)(y − b) = 0 f x (a, b) (x − a) + f y (a, b) (y − b) = 0 ...

  6. Feb 22, 2019 · The text book question is $f(x,y)=xy$, find the gradient vector $\nabla f(3,2)$ and use it to find the tangent line to the level curve $f(x,y)=6$ at the point $(3,2)$.

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  8. Nov 20, 2023 · Using the derivative to find a tangent. At any point on a curve, the tangent is the line that goes through the point and has the same gradient as the curve at that point. For the curve y = f (x), you can find the equation of the tangent at the point (a, f (a)) using.

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