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Sep 3, 2018 · When you get $f'(x)$ plug in the value $x=1$ to get a y value. That will be the gradient of the tangent to the curve $f(x)$. Then write $y=mx+b$, filling in $m$ with whatever you got for the gradient. Then plug in $(1,0)$ and solve for $b$ $\endgroup$ –
- Tangent Line to a Level Curve
find the points (a, b) (a, b) of the plane that satisfy the...
- Tangent Line to a Level Curve
Nov 4, 2015 · Tangent Line to a given level curve Folders: https://drive.google.com/open?id=0Bzl...
- 37 min
- 10.4K
- Calc STCC Math Department Professor R.Burns
Tangents to level curves. Bob Davis. 598 subscribers. Subscribed. 6. 881 views 3 years ago Calculus III. Finding the equation of a tangent line to a level curve at a given point....
- 7 min
- 1472
- Bob Davis
find the points (a, b) (a, b) of the plane that satisfy the tangent of the level curve M = f(a, b) M = f (a, b) in the point (a, b) (a, b) passes through (0, 1) (0, 1). I tried solving this simply by using the equation of the tangent to a level curve: fx(a, b)(x − a) +fy(a, b)(y − b) = 0 f x (a, b) (x − a) + f y (a, b) (y − b) = 0 ...
Given an $n\geq2$, a function $f: \>{\Bbb R}^n\to{\Bbb R}$, and a point $p$ define $q:=f(p)$. The set $$S:=f^{-1}(q)=\{x \>|\>f(x)=q\}$$ is called the level line (or level surface) of $f$ through $p$.
The tangent line to a curve at a given point is the line which intersects the curve at the point and has the same instantaneous slope as the curve at the point. Finding the tangent line to a point on a curved graph is challenging and requires the use of calculus; specifically, we will use the derivative to find the slope of the curve.
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To find where a tangent meets the curve again, first find the equation of the tangent. Then use simultaneous equations to solve both the equation of the tangent and the equation of the curve. Each pair of x and y solutions corresponds to a coordinate (x, y) where the tangent intersects the curve.
