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Jun 28, 2016 · The result is 1 because compareTo() returns 0 if the arguments are equal, -1 if the first int is smaller than the second one and 1 if the second one is smaller (you can read more about it in the official docs). --> You should not use this method for this purpose. Calculate the difference instead: int x = pos2.x - pos1.x; int y = pos2.y - pos1.y;
- Using The Math.abs() Method
- The Overflow/Underflow Issue
- Using A Different Datatype
- Throwing An Exception When Overflow/Underflow occurrs
- Conclusion
The problem is pretty straightforward. Let’s understand it quickly with a few examples: 1. num1=3, num2=4: absDiff=1 2. num1=3, num2=-4: absDiff=7 3. num1=-3, num2=-4: absDiff=1 Looking at the examples above, given two integers, num1 and num2, the result is the absolute value of (num1 – num2). Further, Java standard library has provided the Math.ab...
We know that Java’s int is a signed 32-bit integer. In other words, the Java integer’s range is -2147483648 to 2147483647. Now, let’s revisit our implementation. We have the calculation: num1 – num2. Therefore, the result could exceed Integer.MAX_VALUE, for example, when we pass Integer.MAX_VALUE and -200 to the absDiff()method. Next, let’s call th...
In Java, there are number types with ranges larger than int, such as long or BigInteger. To avoid overflow/underflow pitfalls, we can convert int parameters to one of those types before performing the calculation. Let’s pick longas an example and implement the logic in a new method: Now, let’s test if it gives us the expected result when we pass In...
Let’s say our program requires the absolute difference result as an int. Then the ideal behavior of the method would be returning an int and raising an exception when overflow/underflow occurs. However, as we’ve seen earlier, Java doesn’t throw an exception when an overflow occurs during the regular (num1 – num2)calculation. This makes it hard to f...
In this article, we’ve explored calculating the absolute difference between two integers. Further, we’ve discussed the overflow/underflow issue. As usual, all code snippets presented in the article are available over on GitHub.
- Kai Yuan
Nov 17, 2021 · 3. Is there a method in the Java Math class that returns the absolute difference of two integers? No, but you can just use Math.abs() to turn the difference into an absolute difference. Note that the absolute difference between two int values may not be expressible as an int. It can be >= 2^31.
Sep 17, 2024 · This method returns the absolute value of any integer or floating-point number passed to it. Basic Syntax: int absoluteDifference = Math.abs(a - b); Where a and b are the two numbers, and Math.abs () computes the absolute value of the difference. Step-by-Step Example: Let’s break down the process with a simple example:
Basic Java Project: Create a new Java project in your IDE. Implementing Absolute Difference in Java. Let's start coding the absolute difference of two integers. We will write a simple program that prompts the user to enter two integers and then displays the absolute difference. Step 1: Create the Java Class
Here are a couple of examples to help you understand it better: num1=3, num2=4: absDiff=1; num1=3, num2=-4: absDiff=7; num1=-3, num2=-4: absDiff=1; When you have two integers, num1 and num2, the result you get is the absolute value of (num1 – num2). In Java, you can use the Math.abs() method from the standard library to find the absolute ...
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Feb 12, 2024 · Compare Two Integer Values in Java Using Relational Operators. In Java programming, the comparison of integers is a fundamental aspect, serving as the basis for decision-making and logical operations. One common approach is to use relational operators, such as <, <=, >, >=, ==, and !=, to establish relationships between numbers.
