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      • We can calculate the gradient of a tangent to a curve by differentiating. In order to find the equation of a tangent, we: Differentiate the equation of the curve Substitute the (x) value into the differentiated equation to find the gradient Substitute the (x) value into the original equation of the curve to find the y-coordinate
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  1. Step 1. Differentiate the function of the curve. If , then. Step 2. Substitute the x-coordinate of the given point into this derivative to find the gradient, ‘m’. The gradient anywhere on the curve is found by the gradient function, . The tangent is at the point (1, 3). Here, x=1.

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  2. Nov 16, 2022 · In this section discuss how the gradient vector can be used to find tangent planes to a much more general function than in the previous section. We will also define the normal line and discuss how the gradient vector can be used to find the equation of the normal line.

  3. To determine the equation of a tangent to a curve: Find the derivative using the rules of differentiation. Substitute the \ (x\)-coordinate of the given point into the derivative to calculate the gradient of the tangent.

  4. Sep 4, 2014 · The gradient of a function is also known as the slope, and the slope (of a tangent) at a given point on a function is also known as the derivative. To find the gradient, take the derivative of the function with respect to x, then substitute the x-coordinate of the point of interest in for the x values in the derivative.

  5. Aug 17, 2024 · Use the gradient to find the tangent to a level curve of a given function. Calculate directional derivatives and gradients in three dimensions. A function \(z=f(x,y)\) has two partial derivatives: \(∂z/∂x\) and \(∂z/∂y\).

  6. Dec 29, 2020 · Example \(\PageIndex{8}\): Using the gradient to find a tangent plane. Find the equation of the plane tangent to the ellipsoid \( \frac{x^2}{12} +\frac{y^2}{6}+\frac{z^2}{4}=1\) at \(P = (1,2,1)\). Solution

  7. The tangent line to a curve at a given point is a straight line that just "touches" the curve at that point. So if the function is f(x) and if the tangent "touches" its curve at x=c, then the tangent will pass through the point (c,f(c)).

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