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Sep 12, 2024 · Now that you have the slope of the perpendicular line, you can plug the value of the slope and the point you were given into a slope equation. This will give you the value of the y-intercept. Using the y-intercept, you can move on to complete the slope equation. [5]
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To find the equation of a line that is perpendicular to a given line, you need the slope of the given line and the point at which the perpendicular line should pass. Perpendicular lines have negative reciprocal slopes, so if you know the slope of the given line, you can use it to find the slope of the perpendicular line.
Find the equation of the line that is: parallel to y = 2x + 1; and passes though the point (5,4) The slope of y = 2x + 1 is 2. The parallel line needs to have the same slope of 2. We can solve it by using the "point-slope" equation of a line: y − y 1 = 2(x − x 1) And then put in the point (5,4): y − 4 = 2(x − 5) That is an answer!
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4 Simplify and solve the equation. 5 Substitutec = 3 into the equation yxc Practice questions 1 Find the equation of the line perpendicular to y = x – 3 which passes through the point (–5, 3). 2 Find the equation of the line perpendicular to each of the given lines and which passes through each of the given points. a y = 2x – 6 (4, 0) b y ...
First, find the perpendicular gradient and substitute this into the equation for all straight lines, \(y = mx + c\). If \(y = 3x - 1\) the gradient of the graph is 3.
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Purplemath. There is one other consideration for straight-line equations: finding parallel and perpendicular lines.Here is a common format for exercises on this topic: Given the line 2x − 3y = 9 and the point (4, −1), find lines, in slope-intercept form, through the given point such that the two lines are, respectively,:
