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A universal set is given by 2 = {2, 4, 6, 8, 10, 12, 14). If we define two sets A = {2, 4.8} and B = {4, 6, 8, 12) determine the following: (a) Ā (b) B-A (c) AUB (d) AB (e) AB (1) ( AB) ( AB)
You can put this solution on YOUR website! use the following sets: U = (2,4,6,8,10,12,14) A = (4,6,8), B = (2,6,10,12), C = (2,8,14) Find A U B A. (4,6,8,2,6,10,12) B ...
- Universal Set Definition
- Symbol of Universal Set
- Example of Universal Set
- Complement of Universal Set
The universal set is the set of all elements or members of all related sets. It is usually denoted by the symbol E or U. For example, in human population studies, the universal set is the set of all the people in the world. The set of all people in each country can be considered as a subset of this universal set. 1. A universal set can be either a ...
The universal set is represented by the symbol E or U. It consists of all the elements of its subsets, along with some extra elements.
Let's consider an example with three sets, A, B, and C. Here, A = {2, 4, 6}, B = {1, 3, 7, 9, 11}, and C = {4, 8, 11}. We need to find the universal set for all three sets A, B, and C. All the elements of the given sets are contained in the universal set. Thus, the universal set U of A, B, and C can be given by U = {1, 2, 3, 4, 6, 7, 8, 9, 10, 11, ...
For a subset A of the universal set (U), its complement is represented as A' which includes the elements of the universal set but not the elements of set A. The universal set consists of a set of all elements of all its related subsets, whereas the empty set contains no elements of the subsets. Thus, the complement of the universal set is an empty ...
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Apr 16, 2024 · A ∩ B = {2, 4, 6, 8} ∩ { 6, 8, 10, 12} 6, 8 are the only elements which are common to both A and B. = {6, 8} ∩ Intersection – Common of two sets.
According to the question, A = {2, 4, 6, 8, 12, 20}, B = {3, 6, 9, 12, 15}, C = {5, 10, 15, 20} Here, U is a universal set. Therefore, ⇒ A ∩ B = {2, 4, 6, 8, 12, 20}∩ {3, 6, 9, 12, 15} = {6, 12}, ⇒ B ∩ C = {3, 6, 9, 12, 15}∩ {5, 10, 15, 20} = {15}, ⇒ A ∩ C = {2, 4, 6, 8, 12, 20}∩ {5, 10, 15, 20} = {20},
