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Jan 21, 2021 · Definition 6.3.1 6.3. 1: z-score. z = x − μ σ (6.3.1) (6.3.1) z = x − μ σ. where μ μ = mean of the population of the x value and σ σ = standard deviation for the population of the x value. The z-score is normally distributed, with a mean of 0 and a standard deviation of 1. It is known as the standard normal curve.
- Example 1: Probability Less Than A Certain Value
- Example 2: Probability Greater Than A Certain Value
- Example 3: Probability Between Two Values
The scores on a certain test are normally distributed with mean μ = 82 and standard deviation σ = 8. What is the probability that a given student scores less than 84 on the test? Step 1: Find the z-score. First, we will find the z-score associated with a score of 84: z-score = (x – μ) / σ = (84 – 82) / 8 = 2 / 8 = 0.25 Step 2: Use the z-table to fi...
The height of a certain species of penguin is normally distributed with a mean of μ = 30 inches and a standard deviation of σ = 4 inches. If we randomly select a penguin, what is the probability that it is greater than 28 inches tall? Step 1: Find the z-score. First, we will find the z-score associated with a height of 28 inches. z-score = (x – μ) ...
The weight of a certain species of turtle is normally distributed with a mean of μ = 400 pounds and a standard deviation of σ = 25 pounds. If we randomly select a turtle, what is the probability that it weighs between 410 and 425 pounds? Step 1: Find the z-scores. First, we will find the z-scores associated with 410 pounds and 425 pounds z-score of...
Apr 2, 2023 · x = μ + (z)(σ) = 5 + (3)(2) = 11. The z -score is three. Since the mean for the standard normal distribution is zero and the standard deviation is one, then the transformation in Equation 6.2.1 produces the distribution Z ∼ N(0, 1). The value x comes from a normal distribution with mean μ and standard deviation σ.
Nov 5, 2020 · The z score tells you how many standard deviations away 1380 is from the mean. Step 1: Subtract the mean from the x value. x = 1380. M = 1150. x – M = 1380 − 1150 = 230. Step 2: Divide the difference by the standard deviation. SD = 150. z = 230 ÷ 150 = 1.53. The z score for a value of 1380 is 1.53.
- Suppose X ~ N(5, 6). This says that X is a normally distributed random variable with mean μ = 5 and standard deviation σ = 6. Suppose x = 17.
- Some doctors believe that a person can lose five pounds, on the average, in a month by reducing their fat intake and by exercising consistently.
- The mean height of 15 to 18-year-old males from Chile from 2009 to 2010 was 170 cm with a standard deviation of 6.28 cm. Male heights are known to follow a normal distribution.
- Problem. From 1984 to 1985, the mean height of 15 to 18-year-old males from Chile was 172.36 cm, and the standard deviation was 6.34 cm. Let Y = the height of 15 to 18-year-old males from 1984 to 1985.
You can use our normal distribution probability calculator to confirm that the value you used to construct the confidence intervals is correct. For example, if X = 1.96, then X is the 97.5 percentile point of the standard normal distribution. (Set mean = 0, standard deviation = 1, and X = 1.96. See that 97.5% of values are below the X.)
Oct 23, 2020 · The empirical rule, or the 68-95-99.7 rule, tells you where most of your values lie in a normal distribution: Around 68% of values are within 1 standard deviation from the mean. Around 95% of values are within 2 standard deviations from the mean. Around 99.7% of values are within 3 standard deviations from the mean.