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  1. What is the time-averaged power supplied to the wave by the string vibrator? Strategy. The power supplied to the wave should equal the time-averaged power of the wave on the string. We know the mass of the string (m s) , the length of the string (L s) , and the tension (F T) in the string. The speed of the wave on the string can be derived from ...

  2. The time-averaged power of a sinusoidal wave is proportional to the square of the amplitude of the wave and the square of the angular frequency of the wave. This is true for most mechanical waves. If either the angular frequency or the amplitude of the wave were doubled, the power would increase by a factor of four.

  3. The time-averaged power of a sinusoidal wave is proportional to the square of the amplitude of the wave and the square of the angular frequency of the wave. This is true for most mechanical waves. If either the angular frequency or the amplitude of the wave were doubled, the power would increase by a factor of four.

  4. All these pertinent factors are included in the definition of intensity \(I\) as power per unit area: \[I = \frac{P}{A}\] where \(P\) is the power carried by the wave through area \(A\). The definition of intensity is valid for any energy in transit, including that carried by waves. The SI unit for intensity is watts per square meter \((W/m^2)\).

  5. Waves are oscillatory disturbances in physical quantities, like light waves, sound waves, or transverse oscillations of a string. These disturbances take energy to create and propagate, in order to move the constituent particles or change the electric/magnetic fields. The power of a wave is therefore energy transported per unit time by the oscillations of a particular wave. The derivation of a ...

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  7. Mar 28, 2024 · where \(T\) is the period of the wave, and \(v=\lambda/T\) is the speed of the wave. The power transmitted by a wave on a rope is thus given by: \[P=\frac{1}{2}\omega ^{2}\mu A^{2}v\] We can see that the power transmitted by a wave goes as the amplitude, \(A\), of the wave squared. It thus takes four times more energy to double the amplitude of ...

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