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- Dictionaryfunction/ˈfʌŋ(k)ʃn/
noun
- 1. an activity that is natural to or the purpose of a person or thing: "bridges perform the function of providing access across water" Similar
- 2. a relation or expression involving one or more variables: "the function (bx + c)"
verb
- 1. work or operate in a proper or particular way: "her liver is functioning normally" Similar Opposite
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Mar 1, 2015 · Improve this answer. answered. 14 19. Add a comment. On the assumption that you have defined the functions u[x], a[x] and b[x] elsewhere, you can define a function as follows: f[x_] := u'[x] + a[x] u[x] + b[x] However, I recommend you read through the documentation on defining functions. Share.
Mar 27, 2023 · I have a totally antisymmetric function of n arguments, f[a,b,c,d] = -f[b,a,c,d], which I would like to be multi-linear, e.g. f[a+x,b+y,c,d] = f[a,b,c,d] + f[x,b,c,d] + f[a,y,c,d] + f[x,y,c,d] How can I achieve this? It's easy enough to do for one argument, e.g. I could use. f[a_Plus,b__]:= f[#,b]&/@a, however I need this to work for all n ...
Souler. 11 1 1 3. 2. use := instead of = and read about Set and SetDelayed. – eldo. Oct 18, 2015 at 17:53. 3. Note that if you do not include a space between x and y in xy, the latter will be considered as an independent variable of name xy. This being said, defining f[x_, y_] = (y/x) + x y and asking for f[1, 2] works fine for me and returns 4.
I need to define a function using the output of series, i.e. f[x_,M_]:= Normal[Series[Sin[x],{x,0,M}]]; Now, for reasons explained in Normal [Series [ ]] does not give a normal expression that I can't fully understand (due inexperience and lack of time), the above code does not work as is. I've managed to use f within other functions, like.
Each function should document any side effects it makes. Things like creating a file, or updating a file, and such are considered a side-effect and can't be prevented by the language. But should be documented in the function header, so someone reading this function later on, can see right away what are its side-effects. $\endgroup$ –
May 18, 2016 · f2[x_,n_]=D[f1[x,n],x] I need to be able to define the derivative of f1 as a new function f2. I have two issues. First, I cannot figure out how to specify that c[[n]] is a constant. The second is, I think that Mathematica is evaluating the differential each time f2 is called. It would be better if Mathematica would evaluate the differential and ...
Usually, we define a function as . F[x_] := x + 10 where the right-hand side is an expression. Now, I would like define a function where the right-hand side is the solution of a set of equations. Like . optV[V_, r_, λ_, μ_, η_, σ_] := V /.
Oct 28, 2016 · Like in C++, you can define such a function as. //do something. return something; and then in the main function we can call this function. How can we do something like this in Mathematica? If I look for function on google, all I get is the function in the sense f [x_]:=x^2. Edit: I want to do the following for example.
Feb 4, 2018 · One other possibility is to simply chain the functions together: f[x_] := Table[#[[i,i]] + #[[i+1,i+1]], {i,1,2 N - 1, 2}] & [Msum[x]] This constructs a function which takes x as the argument, calculates Msum[x], and passes it inside into a function which calculates the requested Table. At this point it's equally simple to just create f such ...
Define a function with a condition. Ask Question Asked 6 years, 9 months ago. Modified 6 years, 9 months ago.
