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Chord of a Circle Examples. Example 1: In the given circle, O is the center, and AB which is the chord of circle is 16 cm. Find the length of AD if OM is the radius of the circle. Solution: We know that the radius of a circle is always perpendicular to the chord of a circle and it acts as a perpendicular bisector.
- Segment of Circle
A segment of a circle is the region that is bounded by an...
- Radius
The diameter is a straight line passing through the center...
- Pythagoras Theorem
The Pythagoras theorem states that if a triangle is a...
- Arc Length
Radius and chord length: Substitute the values of radius and...
- Circumference
The diameter of the circle is the longest chord that passes...
- Area of a Circle
Diameter: A line that passes through the center and its...
- Diameter
Diameter of a Circle. The diameter of a circle is a line...
- Segment of Circle
bisects (cuts in half) the chord; passes through the center of the circle. If a line through a chord has two of these properties, it also has the third. A line that is perpendicular to a chord and bisects it must pass through the center of the circle. A line that is perpendicular to a chord and passes through the center of the circle must ...
Answer. Since 𝑀 is the center of the circle and line 𝑀 𝐷 bisects chord 𝐴 𝐵 at 𝐶, we can apply the chord bisector theorem, which states that if we have a circle with center 𝑀 containing a chord 𝐴 𝐵, then the straight line that passes through 𝑀 and bisects chord 𝐴 𝐵 is perpendicular to 𝐴 𝐵. Hence, we can ...
The perpendicular bisector of a chord is a line passing through the center of the circle such that it divides the chord into two equal parts and meets the chord at a right angle. A circle is a 2D figure without corners or edges such that all the points on the boundary are equidistant from the center. The line segment connecting the center with ...
$\begingroup$ Prove that the line from the center of the circle to the midpoint of the chord is the perpendicular bisector. And since the perpendicular bisector of any segment is unique the center lies on the perpendicular bisector of the chord. $\endgroup$ –
The Converse of this Theorem: The line drawn through the centre of a circle to bisect a chord is perpendicular to the chord. Proof: Consider the same figure, as given above. Assume that AB is the chord of a circle with centre “O”. The centre “O” is joined to the midpoint “X” of the chord AB. Now, we need to prove OX ⊥ AB.
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Aug 16, 2020 · Perpendicular bisector of a chord. A chord is any line drawn across a circle, from one point on the circumference to another: The perpendicular bisector of a chord is the line that cuts the chord in half, at a right angle: The perpendicular bisector of a chord passes through the centre of the circle. This theorem is covered in this video on ...
