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The diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints are on the circumference of the circle. The given end points of the diameter are (−3,8) (- 3, 8) and (7,6) (7, 6). The center point of the circle is the center of the diameter, which is the midpoint between (−3,8) (- 3, 8 ...
Jul 31, 2024 · The equation of a circle is (x-4)² + (y-6)² = 8. You can find this equation by using the following steps: Find the x-coordinate (h) & y-coordinate (k) of the center of the circle by taking the summation of x-coordinates & y-coordinates of the endpoints of the diameter respectively and dividing by 2. Calculate the distance between (6,4) and (2 ...
This video goes through one example of how to write the equation of a circle given the endpoints of the diameter. This could be covered in a Geometry class,...
- 4 min
- 1376
- Cole's World of Mathematics
r 2 (1) = p 2. r = p. where p is the radius of the circle. Example: Find the equation of the circle in the polar form provided that the equation of the circle in standard form is: x 2 + y 2 = 9. Solution: To find the equation of the circle in polar form, substitute the values of x x and y y with: x = rcosθ. y = rsinθ.
Example calculating midpoint and distance to find the equation of a circle given two endpoints of the diameter.
Oct 24, 2016 · First, we have to find the centre of the circle. This will be halfway between the two endpoints #(3+(-5))/2 =-1#, #(6+2)/2=4# giving us the point #(-1,4)# for the centre. now we need to find the radius, take the middle and an end point and find the distance, #((3)-(-1)#, #(6)-(4))# giving us #(4,2)# or 4 our units horizontal and two vertical.
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So when we plot these two equations we should have a circle: y = 2 + √[25 − (x−4) 2] y = 2 − √[25 − (x−4) 2] Try plotting those functions on the Function Grapher. It is also possible to use the Equation Grapher to do it all in one go.
