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  1. Sep 3, 2018 · Find the equation of the tangent line of $e^{x-y}(2x^2+y^2)$ at the point $(1,0)$ at the level curve. So I start finding the gradient of the function $gradf={e^{x-y}(2x^2+y^2)+4xe^{x-y} \choose -e^{x-y}(2x^2+y^2)+2ye^{x-y}}$

  2. Finding the equation of a tangent line to a level curve at a given point. ...more.

    • 7 min
    • 1472
    • Bob Davis
  3. Nov 20, 2023 · Using the derivative to find a tangent. At any point on a curve, the tangent is the line that goes through the point and has the same gradient as the curve at that point. For the curve y = f (x), you can find the equation of the tangent at the point (a, f (a)) using.

  4. find the points (a, b) (a, b) of the plane that satisfy the tangent of the level curve M = f(a, b) M = f (a, b) in the point (a, b) (a, b) passes through (0, 1) (0, 1). I tried solving this simply by using the equation of the tangent to a level curve: fx(a, b)(x − a) +fy(a, b)(y − b) = 0 f x (a, b) (x − a) + f y (a, b) (y − b) = 0 ...

  5. Nov 4, 2015 · 10K views 8 years ago. Tangent Line to a given level curve Folders: https://drive.google.com/open?id=0Bzl......more.

    • 37 min
    • 10.4K
    • Calc STCC Math Department Professor R.Burns
  6. Jan 17, 2019 · An A Level Maths Revision tutorial on finding the equation of a tangent to a curve by differentiation. https://ALevelMathsRevision.com For more information o...

    • 4 min
    • 3.7K
    • A Level Maths Tutor
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  8. Aug 17, 2024 · Use the gradient to find the tangent to a level curve of a given function. Calculate directional derivatives and gradients in three dimensions.

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