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The divisibility rule of 4 tells that a number is said to be divisible by 4 if the last two digits of the number are zeros or they form a number that is divisible by 4. For example, 2300 is divisible by 4 because there are two zeros in the end of the number. Similarly, 488 is also divisible by 4 because the last two digits 88 are divisible by 4.
Divisibility Rule of 9 with Examples. Example 1: Using the divisibility rule of 9, state whether 724 is divisible by 9 or not. Solution: Let us find the sum of all the digits of the number 724. 7+2+4 = 13. Here, 13 is not divisible by 9, so as per the divisibility test of 9, we can say that 724 is not divisible by 9.
The divisibility rule of 4 states that a given number is said to be divisible by 4 if the number formed by the last two digits is divisible by 4. For example, in the number 2348, the last two digits form the number 48 which is divisible by 4. Therefore, 2348 is divisible by 4. However, we know that the divisibility rule of 8 states that if the ...
Answer: For a number to be divisible by 4, the last two digits of the number should be divisible by 4. If the last two digits of a number are divisible by 4, then that number is a multiple of 4 and is completely divisible by 4. Explanation: Let's take an example. Consider the number 563492. The last two digits of the number (92) are divisible by 4.
According to the divisibility rule of 3, any big number is exactly divisible by 3 if the sum of the digits is a multiple of 3. For example, the number 2,146,497 is exactly divisible by 3, where quotient = 715,499 and remainder = 0. The sum of all digits is 2 + 1 + 4 + 6 + 4 + 9 + 7 = 33 and 33 is exactly divisible by 3.
Example: Check if the given number is divisible by 7 or not: 458409. Solution: Let us check if the given number, 458409 is divisible by 7 or not using the following steps: Step 1: We first take the last digit and multiply it by 2. So, (9 × 2 = 18). Subtract 18 with the rest of the number, which is 45840.
Solution: Let us apply the divisibility rule of 11 on this number. Sum of the digits at odd places (from the left) = 7 + 4 + 5 = 16. Sum of the digits at even places = 6 + 8 + 2 = 16. Difference between the sum of the digits at odd and even places = 16 - 16, which is 0. Therefore, 764852 is divisible by 11.
A number is divisible by 2 if the digit on the units place of the number is even, i.e., it is 0, 2, 4, 6, and 8. The given whole number should be divisible by 3. A number is divisible by 3 if the sum of all digits of the number is exactly divisible by 3. Both the conditions should apply to the number while doing the divisibility test of 6.
Multiply the last digit by 9 and find the difference between the product and the rest of the number to the left. If the resulting number is a multiple of 13, then the number is divisible by 13. Step 1: Multiply the last digit by 9. (9 × 9) = 81. Step 2: Subtract 81 from 276. 276 - 81 = 195.
List of First 20 Multiples of 9. Multiplication is repeated addition. For example, 9 + 9 = 2 × 9 = 18 and 9 + 9 + 9 + 9 = 4 × 9 = 36. Thus, 18 and 36 are the 2 nd and 4 th multiples of 9 respectively, which can be obtained by adding 9 repeatedly or by simply multiplying 9 with the integers 2 and 4. The other way is to multiply 9 with natural ...
